幫幫手計條數
有一個袋, 應該係CE Maths 來的?這是高考學術~.~ 原帖由 Zend 於 13-5-2008 01:47 發表 http://www1.nakuz.com/bbs/images/common/back.gif
應該係CE Maths 來的?
這是高考學術~.~
就係你地高一個lv 我都唔係好記得 XD, 過左2年
G- Gold
S- Silver
P(S|G) =P(S&G)/P(G)
P(S) = P(S,G or S,S)
P(G) = P(G,G or S,G) P(金&銀) = 1/3
P(金) = 1/3 + 1/3 * 1/2
P(金&銀)/P(金) = (1/3) / (1/3 + 1/3 * 1/2)
唔肯定. the answer must be 1 but 1面金1面銀 coin hv a 1/2 possibility to show up as silver.
this is my thought, or i will be the same as u. AtMa 好耐都無出現過[] 原帖由 AtMa 於 14-5-2008 18:14 發表 http://www1.nakuz.com/bbs/images/common/back.gif
the answer must be 1 原帖由 bnn9394 於 15-5-2008 11:55 發表 http://www2.nakuz.com/bbs/images/common/back.gif
但網上答案話有個金幣有兩面金色,機會大d抽中,所以1/3
而家given 抽到果個金幣係有一面金
所以之前果個抽0既機率係唔洗計
抽中的coin看到的一面 抽到的coin的另一面
/GOLD (1/2) <~~~~~~~~~而家係搵呢個, 之前呢個igore
GOLD(1/2)---------------
/ \SILVER (1/2)
/
\
\
SILVER (1/2) ---------------...........
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