F.4 Amaths>>>>trigo~~
我想問下面呢兩條數點做???我做極都做唔到...
同埋做D PROVE的TRIGO有冇D咩方法?
有冇D咩技巧會做快D?
THX![][]
Q1係prove,Q2係SOLVE
[ 本帖最後由 Sheep~ 於 16-6-2008 23:40 編輯 ] 1. 煩字C = 180 - (A+B)
2. product to sum 應該唔難. 我試過product to sum <<<
平時轉完應該有舊野約左..
但係做到呢步就做唔到..
之後就唔識解~ 原帖由 Sheep~ 於 15-6-2008 18:57 發表 http://www.nakuz.com/bbs/images/common/back.gif
我試過product to sum
應該係計錯左d野
我n年前都做過第2題...我記得都係用 p to s去搞...第1題係煩到hihi 2)
sin6xsinx =2sin3xcos3xsinx
sin6xsinx=cos3xcos4x
sin6xsinx-cos3xcos4x=0
2sin3xcos3xsinx-cos3xcos4x=0
cos3x(2sin3xsinx-cos4x)=0
cos3x (2(-1/2)(cos4x-cos2x)-cos4x)=0
cos3x(cos2x-2cos4x)=0
cos3x = 0 or cos2x=2cos4x
cos4x =2cos^2 2x -1
solve it
sinA/2+sinB/2+sinC/2 =1+sin(45'-A/4)sin(45'-B/4)sin(45'-C/4)
let A= 30'
B = 60'
C=90'
A/2 =15'
B/2 =30'
C/2 = 45'
A/4 =7.5'
B/4=15'
C/4 = 22.5'
sinA/2+sinB/2+sinC/2 = sin15'+sin30'+sin45'=1.4659
1+sin37.5sin30sin22.5=1.1164 =.="?
[ 本帖最後由 Zend 於 16-6-2008 01:44 編輯 ] 原帖由 Zend 於 16-6-2008 01:13 發表 http://www.nakuz.com/bbs/images/common/back.gif
2)
sin6xsinx =2sin3xcos3xsinx
sin6xsinx=cos3xcos4x
sin6xsinx-cos3xcos4x=0
2sin3xcos3xsinx-cos3xcos4x=0
cos3x(2sin3xsinx-cos4x)=0
cos3x (2(-1/2)(cos4x-cos2x)-cos4x)=0
cos3x(cos2x-2cos4x)=0
cos3 ...
I wonder if 樓主 wants us to simplify or prove Q.2[] sin6xsinx=cos3xcos4x
let x =10' (if we need to prove ge wa)
sin60sin10=0.1503
cos3xcos4x = cos30cos40=0.6634 佢呢係就係叫你搵個x,可以就咁sub數入去咩??
x^2+x=5
sub x=10,
l.h.s=110
r.h.s.=5
所以條數有問題?? 原帖由 piyopiyo 於 16-6-2008 08:30 AM 發表 http://www.nakuz.com/bbs/images/common/back.gif
I wonder if 樓主 wants us to simplify or prove Q.2[]
所以我用contradiction 證明唔係simplify lor =.=.... 通常simplify 都唔會係equation-.- 唔駛證掛...
頁:
[1]
2