log (x+1) = 1 + log x
log (x+1) = log 10 + log x
log (x+1)= log 10x
x+1 = 10x
x = 1/9
應該冇錯? 原帖由 隨風而散” 於 29-11-2008 13:12 發表 http://www1.nakuz.com/bbs/images/common/back.gif
1.log (X+1) - log X = 1
log (x+1) = 1 + log x
log (x+1) = log 10 + log x
log (x+1)= log 10x
x+1 = 10x
x = 1/9
應該冇錯?
岩呀,
我係中四教log=.= 原帖由 。黑仔。 於 3-11-2008 20:00 發表 http://www4.nakuz.com/bbs/images/common/back.gif
log1轉唔到10
logx=1就可以轉到10
你可以試下禁機狂試..
我中5先教log==
你中4教log.. 你學校真係幾勁!!
我都中4教緊- -v
好難 1. log (X+1) - log X = 1
2. 2^x =7
好簡單既LOG數咋喎
1.
log(x+1) - log x = 1
log((x+1)/x) = log 10
(x+1)/x = 10
x+1 = 10x
x = 1/9
2.
2^x = 7
x(log 2) = (log 7)
x = log 7/log 2
x = 2.81, cor. to 3 sig. fig.
呢d已經係最淺既log數= =
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