有冇人讀ms or 識limit?
點算好...聽日考..
救我
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1.)find domain and range of g(x)=(x2-1)/(x2-3x+2)
domain姐係x個range
range姐係g(x)個range
2.)find lim f(x) x-->c+ , x-->c- 同理 x-->c
http://lsforum.net/board/attachments/20081130_7d435c785a96488665388JhTzjjcxz8v.jpg
http://lsforum.net/board/attachments/20081130_2aed6a571e47e974703e0paqXbRjwLqa.jpg
[ 本帖最後由 L.K. 於 30-11-2008 18:56 編輯 ] 1.)find domain and range of g(x)=(x^2-1)/(x^2-3x+2)=(x-1)/(x-2) = 1 + 1/(x-2)
domain = all real number exclude 2
range = all real number exclude 1
都係估.
2.)find lim f(x) x-->c+ , x-->c- 同理 x-->c
條問題未免簡單左d.... 原帖由 【YU】 於 30/11/2008 08:13 PM 發表 http://www4.nakuz.com/bbs/images/common/back.gif
2.)find lim f(x) x-->c+ , x-->c- 同理 x-->c
條問題未免簡單左d....
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唔識...
實點同空點有咩分別... you should learn it in amaths? i did not study amath...
[ 本帖最後由 L.K. 於 1-12-2008 13:15 編輯 ] Oh, 黑點只係果點係 exists
白點唔果點value 唔exists
我地用來證個function 係唔係continous 如果兩個數(lim-->x+同lim---->x-)係一樣個9,個function就係continuous 原帖由 【YU】 於 30-11-2008 20:13 發表 http://www.nakuz.com/bbs/images/common/back.gif
1.)find domain and range of g(x)=(x^2-1)/(x^2-3x+2)=(x-1)/(x-2) = 1 + 1/(x-2)
domain = all real number exclude 2
range = all real number exclude 1
貌似...
g(x)=(x^2-1)/(x^2-3x+2)={(x+1)(x-1)}/{(x-2)(x-1)} --> (x+1)/(x-2) = 1 + {3/(x-2)}
isn't g(x) undefined at x=1 and x=2 ?
事實是我(還)沒學這些... 原帖由 j32738 於 1-12-2008 18:08 發表 http://www1.nakuz.com/bbs/images/common/back.gif
如果兩個數(lim-->x+同lim---->x-)係一樣個9,個function就係continuous
wrong la 原帖由 Puppet 於 1-12-2008 19:01 發表 http://www.nakuz.com/bbs/images/common/back.gif
wrong la
agree[]
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