H2O:
因為O 係sp3 hybridization
所以有4個完全相同sp3
四個sp3會以tetrahedral既樣擺出黎
而H2O既兩個lone pairs of electrons會用左擺兩個頂點
但兩個H 就會放喺tetrahedral既底部兩點
而 ...
Hinton 發表於 10-12-2009 19:17 http://www.nakuz.com/bbs/images/common/back.gif
oh..
即係所有atom form bond果陣都會做hybridization?
因為我見oxygen 2s個orbital full左 以為佢唔會做嫁添-.- 本帖最後由 Hinton 於 29-12-2009 21:33 編輯
唔係任何atom會做hybridization...
e.g. diatomic molecules 入面既atoms
H2既H 冇做hybridization
至於CO2既C係sp
因為C (excited state)
2s 2p
↑|↑|↑|↑|
只需要同兩個atoms form sigma bond(O)
所以只需要1個2s 同1個2p 做hybridization
1個 2s + 1個 2p -> 2個 完全相同既sp
而淨返個兩個p orbital 就分別同左右兩邊既O form pi bond 本帖最後由 paladin 於 10-11-2011 23:38 編輯
not good to say NO2 unstable, NO2 exists with N2O4 in eqm, relative stability depends on pressure, temperature, etc.
why NO2 can't be octet, things adopt most stable form in a given condition, there is no way NO2 can have octet.
C in CO2 sp hybridizes, correct;
triple bond sp hybridizes leading to 2 sigma 2pi, not correct, let say N2, 2 lone pair, 1 sigma, and 2 pi.
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