DicKiT 發表於 12-9-2010 22:12:57

回復 10# -終場ソ使者-
但佢要show 到個relation between (a) and (b)出黎

[H]bunbunbunbun 發表於 13-9-2010 01:40:27

本帖最後由 bunbunbunbun 於 12-9-2010 17:46 編輯

回復 8# p445hkk20001

method of difference
Its much more useful when doing summations involving partial fractions
I reckon this is an example only

basically part a shows that f(x)= g(x)-g(x-1)

so summing f(x) from a to b = summing g(x)-g(x-1) from a to b = g(a) - g(a-1) + g(a) - g(a) +g(a+2)- g(a+1)+...+g(b) -g(b-1)=g(b)-g(a-1)

-終場ソ使者- 發表於 13-9-2010 19:31:50

回復p445hkk20001

method of difference
Its much more useful when doing summations involving parti ...
bunbunbunbun 發表於 13-9-2010 01:40 http://www4.nakuz.com/bbs/images/common/back.gif
Actually, we have not learnt such a Method of difference in M1/M2@@
In that case, using basic concept of summation is already enough.
They may not ace the mothod that you've told.
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