數學問題-三角比(大家幫幫手)
sin30°cos60°-tan^260°唔識計 希望大家可以幫幫手plz! sin30°cos60°-tan^260°
=(1/2)(1/2)-(root 3)^2
=1/4-3
=-11/4 sin30°cos60°-tan^260°
=(1/2)(1/2)-(root 3)^2
=1/4-3
=-11/4
刺客先生 發表於 25-5-2013 21:46 http://www.nakuz.com/bbs/images/common/back.gif
我想請問下個11點黎
同埋點解負數既 唔該哂! 我想請問下個11點黎
同埋點解負數既 唔該哂!
說再見 發表於 25-5-2013 22:03 http://www.nakuz.com/bbs/images/common/back.gif
1/4-3=1/4-12/4=(1-12)/4=-11/4
1/4=0.25
0.25<3
1/4<3
細d既數減大d既數咪負數 tan^260° 係咩尼 ...? tan^260° 係咩尼 ...?
-BOY- 發表於 25-5-2013 23:13 http://www.nakuz.com/bbs/images/common/back.gif
應該係想講tan60°二次方吧 唔可以直接禁機咩?=.= sin30°cos60°-tan^260°
唔識計 希望大家可以幫幫手plz!
說再見 發表於 25-5-2013 21:44 http://www.nakuz.com/bbs/images/common/back.gif
唔比禁計數機:funk:? 用開兀,睇唔慣度數:Q 唔可以直接禁機咩?=.=
qwqw135790 發表於 26-5-2013 00:22 http://www.nakuz.com/bbs/images/common/back.gif
禁機無exact value
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