[H]bunbunbunbun 發表於 27-4-2008 10:15:04

回復 10# 的帖子

你show一下點change in O.N.......
C本身唔係0咩?

16.
個樣似係CHCH form出黎
點睇都唔似係其他= =

piyopiyo 發表於 27-4-2008 10:20:00

C點會係0[]
C係 +4...

[ 本帖最後由 piyopiyo 於 27-4-2008 10:21 編輯 ]

[H]bunbunbunbun 發表於 27-4-2008 10:30:55

回復 12# 的帖子

why+4?
咁你點知H同O係咩

piyopiyo 發表於 27-4-2008 10:53:01

原帖由 bunbunbunbun 於 27-4-2008 10:30 發表 http://www.nakuz.com/bbs/images/common/back.gif
why+4?
咁你點知H同O係咩
唔知wor[]做果陣只是直覺覺得是redox
但而家唸唸下有好似唔係...
呢個係dehydration ...
除非 H是 -1...


http://en.wikipedia.org/wiki/Organic_oxidation

[ 本帖最後由 piyopiyo 於 27-4-2008 10:58 編輯 ]

piyopiyo 發表於 27-4-2008 11:00:35

第2題 why not A[]

[H]bunbunbunbun 發表於 27-4-2008 11:16:48

回復 15# 的帖子

Volume高左
H+ concentration不變
所以pH上升

btw
14點解B= =

[ 本帖最後由 bunbunbunbun 於 27-4-2008 11:18 編輯 ]

piyopiyo 發表於 27-4-2008 11:51:06

原帖由 bunbunbunbun 於 27-4-2008 11:16 發表 http://www.nakuz.com/bbs/images/common/back.gif
Volume高左
H+ concentration不變
所以pH上升

btw
14點解B= =
但都係不變[]

[H]bunbunbunbun 發表於 27-4-2008 11:57:10

回復 17# 的帖子

pH=-log

Puppet 發表於 27-4-2008 12:23:20

1. (3) × Too close b.p.

2.
A. ×
Volume increases => (molarity) decreases => pH = - log , pH increases
Note that the solution is still neutral (assume ethanol is not an acid)
D.
Neutral iff =
At higher temperatures, in pure water = > 10^-7
pH < 7 but the solution is of course neutral

10.
General rule: Free elements as either reactant or products => must be redox (except C(graphite) -> C(diamond))
By conventional methond, C + 12(+1) + 6(-2) = 0 => C = 0
In fact, referring to the structure of glucose (as an example),
O.N. of 4 of the C atoms in C6H12O6 = 0
O.N. of C in aldo group of C6H12O6 = -1
ON. of the other terminal C of C6H12O6 = +1
So, please follow the general rule.

14. should be C
I typed it wrongly

[ 本帖最後由 Puppet 於 27-4-2008 12:25 編輯 ]

777kong 發表於 27-4-2008 19:47:06

seems quite difficult
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