[AL] limit ...(急)
Q1. lim (x+3sinx)/(5cox-2x)x->∞
Q2. lim (√(x^2 - 1))/(x - 1)
x->∞
Q3. lim (√(x^4+1))/(4-x^4)
x->∞
Q4. lim (x^n - y^n)/(x-y)
x->y
Q5. lim(x^n - y^n)/(x-y)
y->x
Q6. suggest a definition for f(x) forlim f(x) = 4, lim f(x)=2 and f(x) is decreasing for all large value |x|
x->+∞ x->-∞
Q1. 我d左個tan出黎....tan∞ 係咩 ?
Q2. 我D黎D去都出返自己... 唔知點搞 -.-
下面果D 有冇人識做 /.\
[ 本帖最後由 octopus001 於 30-11-2008 02:23 編輯 ] sandwich theorem can help u =.=""即係點?[] 係nakuz 答數學題好煩-.- 找條友答你啦
4, 5 都唔識??? 1. 你可以用第2次L'Hôpital's rule嗎?
2. 因式分解 can help you
[ 本帖最後由 Puppet 於 30-11-2008 14:43 編輯 ] http://img266.imageshack.us/img266/7019/abcuj7.jpg
d 海無涯 回頭是岸阿施主
d 咁多無益架[]
[ 本帖最後由 bearwing 於 30-11-2008 23:48 編輯 ] lim x-> infinity sinx/x=0 ?
lim x->infinity cosx/x =0 ?
係唔係應該要證?
唔係果幾個important limits 之一 bor 原帖由 Zend 於 1-12-2008 13:35 發表 http://www.nakuz.com/bbs/images/common/back.gif
lim x-> infinity sinx/x=0 ?
lim x->infinity cosx/x =0 ?
係唔係應該要證?
唔係果幾個important limits 之一 bor
range of sin cos function = [-1,1] 原帖由 【YU】 於 1-12-2008 07:42 PM 發表 http://www.nakuz.com/bbs/images/common/back.gif
range of sin cos function = [-1,1]
證同知係兩回事bor... 原帖由 Zend 於 1-12-2008 19:55 發表 http://www4.nakuz.com/bbs/images/common/back.gif
證同知係兩回事bor...
當年 PM 應該有條 theorem 話:
If f(x) g(x) = 0
f(x) is bounded for all x and lim_(x-> inf) g(x) = 0 => lim_(x-> inf) f(x)g(x) = 0
至於問點解 -1 < sin x, cos x < 1
都係 take it for granted 吧
要証都唔太難,只要寫到個 sin 同 cos o既定義
再証 sin^2 x + cos^2 x = 1,
that IMPLIES sin^2 x <= 1 and cos^2 x <= 1
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