speed A = x/8
speed B = x/6
distance travelled by A in 2 hrs = 2x/8
remaining distance = x - 2x/6
-----------------------------------------------------------------------------------------------
relative speed = x/6 + x/8
time to meet = (x - 2x/8) / (x/6 + x/8) = 18/7 hrs
or
let t be the time to meet, sum of distance travel = remaining distance
xt/6 + xt/8 = x - 2x/6
u will also get the same result by the same calculation after rearrangment.
原帖由 [S]【YU】 於 27-5-2008 17:54 發表
1614 = ELEC1614 = Course Code of Electronic devices and circuits of EE in HKU....
wt is Mechatronic Engineering ? new thing?