我就俾你見識下大陸既數:
factorize:
(a+b-2ab)(a+b-2)+(1-ab)2
6x2-7xy-3y2-zx+7yz-2z2
(x+y)3+2xy(1-x-y)-1
simplify:
(2√6-1)/(√2+√3+√6)
1/(3√4+3√6+3√9)
given that √a+√b+√c=3, and a≠b≠c
find the no. of
[(√a-1)2+(√b-1)2+(√c-1)2]/[(√a-1)(√b-1)+(√b-1)(√c-1)+(√c-1)(√a-1)]