(Force acting on B by A)-Q=Fnet of B-Q
(Force acting on B by A)-Q=2/3X(P-Q)
(Force acting on B by A)-Q=2/3P-2/3Q
Force acting on B by A=2/3P-2/3Q+Q
=2/3P+1/3Q
=(2P+Q)/3N
第一題個計法係點...
我諗緊係咪
因為個mgsin(angle)可以成為水平分力(F)
F/mgsin(angle)=cos(angle)
F=mgsin(angle)cos(angle)
F=(5)(10)sin(arctan 3/4)cos(arctan 3/4)
F=24 Newton?
according to the 3rd of newton's law
the force acting on the wedge from the block is 24 Newton
Hence ,
the force exerted on the wedge should be 24 Newton?
有錯請指正...