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發表於 7-4-2010 13:35:55
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本帖最後由 nomygf 於 7-4-2010 15:09 編輯
1. S=K1(t)+K2/(t) (where k1&k2 is non-zero constant)
When T=1, S=8, we have,
8=K1+K2_____(1)
When T=6, S=13, we have,
13=6K1+K2/6______(2)
(2)->(1)
K1=2
K2=6
Put K1 and K2 into eqt.
S=2t+6/t
2. Z=kxy (where k is non-zero constant)
when x become 0.9x, y become 1.1y, we have
Z=(0.9)(1.1)xy
Z=0.99xy
Pencetage change = (0.99xy-xy)x100%/xy
=-1%
Which mean decrease by 1%
Other questions are using similar method to solve,
try it again !
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