一條簡單的L0G`

yuetstarz

3log4 + 2log5 - log16
=3log2^2 + 2log5 - log2^4
=6log2 + 2log5 - 4log2
=(6x2/4)log(2x5/2)
=3log5

點解我計吾到系2?

只愛您一個

6log2 + 2log5 - 4log2
=2log2+2log5
=log4+log25
=log(4X25)
=2

小山田萬太

3log4 + 2log5 - log16
=3log2^2 + 2log5 - log2^4
=6log2 + 2log5 - 4log2
=(6x2/4)log(2x5/2)
=3log5

點解我計吾到系2?
yuetstarz 發表於 24-1-2009 14:07

=(6x2/4)log(2x5/2)
你呢步點黎-.-??

yuetstarz

有話數字同數字乘既...

Zend

無
而且coefficient 唔同

yuetstarz

設log2=0.3010及log3=0.4771
log12^(1/10)
=1/10 log 12
=1/10 log (2^2x3)
=1/5 log (2x3)
???

Zend

log a^b = bloga

log ca^b=/=blog ca

yuetstarz

呢個我識-,-

-終場ソ使者-

唔好將coefficient同log數混淆
a log x-b log x=(a-b)log x
≠(a/b)log x

就好似:
a√x+b√x=(a+b)√x

Zend

呢個我識-,-
yuetstarz 發表於 25-1-2009 01:14

then you should know why you are wrong la